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 Post subject: Can someone give me the alg that will solve this?Posted: Sat May 05, 2007 9:05 pm

Joined: Sat Apr 28, 2007 9:11 pm
Location: East Coast, USA
All the cube is solved, except for two opposite corners in the LL.

These two corners are permuted properly, but they are disoriented (they are in the right position in relation to the cube but have been rotated).

The corner at BUR is rotated clockwise.
The corner at FUL is rotated counterclockwise.

This algorithm will take care of the orientation of those two corners: (R'F'L') (FR) (F'LF) but it will mess up the edges and permute the other corners.

I need an algorithm that will rotate the corner at BUR counterclockwise and the corner at FUL clockwise, without affecting the rest of the cube.

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 Post subject: Posted: Sat May 05, 2007 9:58 pm

Joined: Wed Apr 11, 2007 7:58 pm
You can use the commutator (R' D' R D) x2 to rotate corners. Other than that, a specific algorithm to solve this position is F' R D2 R' F U2 F' R D2 R' F U2, though I can't see why you need it.

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 Post subject: Posted: Sat May 05, 2007 10:13 pm

Joined: Sat Apr 28, 2007 9:11 pm
Location: East Coast, USA
Paiev wrote:
You can use the commutator (R' D' R D) x2 to rotate corners. Other than that, a specific algorithm to solve this position is F' R D2 R' F U2 F' R D2 R' F U2, though I can't see why you need it.

(F' R D2 R' F U2) x 2 does it. Thanks.

Oh and the reason I need it is in case I ever end up with that configuration after doing F2L. I have actually ended up with that configuration several times.

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 Post subject: Posted: Sun May 06, 2007 8:44 am

Joined: Fri May 06, 2005 10:13 am
Location: Norway
Hi

A single commutator that does this directly is like so :

[F' D F L D L',U2]=F' D F L D L' U2 L D' L' F' D' F U2

Not the shortest or fastest, but straight forward from "first principles"

-Per

_________________
"Life is what happens to you while you are busy making other plans" -John Lennon, Beautiful Boy

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 Post subject: Posted: Sun May 06, 2007 9:36 am

Joined: Sat Apr 28, 2007 9:11 pm
Location: East Coast, USA
is a commutator when you do something like:

A B C D C' B' A'

sort of like unwinding everything you did up to D?

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 Post subject: Posted: Sun May 06, 2007 10:02 am

Joined: Tue Jan 10, 2006 11:15 am
Location: Helsinki, Finland
Rubo d Cubik wrote:
is a commutator when you do something like:

A B C D C' B' A'

No. Commutator = A B A' B', where A and B can be either single moves or move sequences. A = (B R' D2 R B') and B = U2 gives (B R' D2 R B') U2 (B R' D2 R B') U2. This is an exception, though, because A = A' but you get the idea.

What you described is a conjugate, C D C'.

See http://www.geocities.com/jaapsch/puzzles/theory.htm

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 Post subject: Posted: Sun May 06, 2007 10:23 am

Joined: Fri May 06, 2005 10:13 am
Location: Norway
Johannes Laire wrote:
Rubo d Cubik wrote:
is a commutator when you do something like:

A B C D C' B' A'

No. Commutator = A B A' B', where A and B can be either single moves or move sequences. A = (B R' D2 R B') and B = U2 gives (B R' D2 R B') U2 (B R' D2 R B') U2. This is an exception, though, because A = A' but you get the idea.

What you described is a conjugate, C D C'.

See http://www.geocities.com/jaapsch/puzzles/theory.htm

Better to say that A B C D C' B' A' = F C F', where F = A B C.
Avoids notational confusion

-Per

_________________
"Life is what happens to you while you are busy making other plans" -John Lennon, Beautiful Boy

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 Post subject: Posted: Sun May 06, 2007 10:33 am

Joined: Tue Jan 10, 2006 11:15 am
Location: Helsinki, Finland
perfredlund wrote:
Johannes Laire wrote:
Rubo d Cubik wrote:
is a commutator when you do something like:

A B C D C' B' A'

What you described is a conjugate, C D C'.

Better to say that A B C D C' B' A' = F C F', where F = A B C.
Avoids notational confusion

I was actually going to do it that way, but then left it to him to figure out that it's the same thing.

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 Post subject: Posted: Sun May 06, 2007 1:10 pm

Joined: Thu Nov 20, 2003 7:29 am
Location: San Diego, California
R' U2 R U R' U R L U2 L' U' L U' L'

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 Post subject: Posted: Sun May 06, 2007 2:52 pm

Joined: Fri May 06, 2005 10:13 am
Location: Norway
R' U2 R U R' U R L U2 L' U' L U' L'

That twists wrong corners. He asked for opposite corners on same layer

-Per

_________________
"Life is what happens to you while you are busy making other plans" -John Lennon, Beautiful Boy

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 Post subject: Posted: Sun May 06, 2007 5:05 pm

Joined: Sat Apr 30, 2005 6:44 pm
R' U2 R U R' U R L U2 L' U' L U' L'

haha, i learned that one from the rubiks website

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 Post subject: Posted: Sun May 06, 2007 5:15 pm

Joined: Sat Apr 28, 2007 9:11 pm
Location: East Coast, USA
Smapla wrote:
R' U2 R U R' U R L U2 L' U' L U' L'

haha, i learned that one from the rubiks website

That's an interesting alg. Too bad it's not as symmetric as this one: (F' R D2 R' F U2) x 2

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 Post subject: Posted: Sun May 06, 2007 7:31 pm

Joined: Thu Nov 20, 2003 7:29 am
Location: San Diego, California
perfredlund wrote:
R' U2 R U R' U R L U2 L' U' L U' L'

That twists wrong corners. He asked for opposite corners on same layer

-Per

i gave him an alg, he has to learn how to mirror it. i didnt want to give him the whole solution. i could have given him a 2 gen that does the same thing.

R' U2 R U R' U R U2 R U2 R' U' R U' R' U2

L U2 L' U' L U' L' U2 L' U2 L U L' U L U2

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 Post subject: Posted: Sun May 06, 2007 8:06 pm

Joined: Sat Apr 28, 2007 9:11 pm
Location: East Coast, USA
I don't think I am gonna learn anything just by memorizing algorithms. How do I learn to figure these things out?

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 Post subject: Posted: Sun May 06, 2007 11:48 pm

Joined: Thu Nov 20, 2003 7:29 am
Location: San Diego, California
Rubo d Cubik wrote:
Smapla wrote:
R' U2 R U R' U R L U2 L' U' L U' L'

haha, i learned that one from the rubiks website

That's an interesting alg. Too bad it's not as symmetric as this one: (F' R D2 R' F U2) x 2

U' R U R' U' R U L U' R' U R U' R' L'

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 Post subject: Posted: Mon May 07, 2007 2:26 am

Joined: Tue Sep 26, 2006 6:00 am
Location: Shanghai, China
The first algorithm Adam posted is a combination of two Sunes.

I believe the algorithm from Paiev is a commutator in which the X and the Y move (in XYX'Y') is its own inverse, which allows it to be the exact same sequence twice.

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 Post subject: Posted: Mon May 07, 2007 12:19 pm

Joined: Thu Nov 20, 2003 7:29 am
Location: San Diego, California
JIMBOB its one that i learned a long time ago (almost 4 years ago) from the rubiks website. i still use it today for BLD and the occasional luckycase last layer.

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