Joined: Sun Mar 02, 2008 11:33 am Location: Hiram, Ohio
I normally solve this case by turning the two noninvolved faces repeatedly... I.E. if the corners are bottom left front and bottom left back I would do (R U)x7 R
The problem is I am trying to drop my 2x2 time and this algorithm is rather unwieldy..... So can anyone offer me a substitute algorithm?
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