Online since 2002. Over 3300 puzzles, 2600 worldwide members, and 270,000 messages.

TwistyPuzzles.com Forum
 It is currently Tue Dec 10, 2013 4:07 am

 All times are UTC - 5 hours

 Page 1 of 1 [ 7 posts ]
 Print view Previous topic | Next topic
Author Message
 Post subject: Super 5x5x5Posted: Sun Jul 30, 2006 6:42 pm

Joined: Sun Jun 04, 2006 10:05 am
Location: Eastern Michigan University (Minnesota at heart)
I can get all but 1 of the centers solved correctly.

How can I re arrange the last center?

_________________
Fridrich
3x3 PB 22.63
3x3 Av 30.57

20, Male
Started cubing Oct 15 '05

Top

 Post subject: Re: Super 5x5x5Posted: Sun Jul 30, 2006 6:51 pm

Joined: Sun Dec 19, 1999 3:02 am
xcool wrote:
I can get all but 1 of the centers solved correctly.

How can I re arrange the last center?

OK, since it's only 1 centre, I'm guessing that it's the innermost centre and that it's rotated by 180 degrees, correct? I think any other pattern would mean that either the cube was stickered wrong, or it was taken apart and reassembled wrong. So... asuming that it IS the centremost piece and that it is indeed a 180 degree rotation, hold it so that it's on the bottom and then treat the puzzle as though it's a 3x3 so that R and r both count as the R slice, and D and d count as down... then do (R- D- R+ D- R- D2 R+ D2)^3 and you're done! Hooray! L8r.

Top

 Post subject: Re: Super 5x5x5Posted: Sun Jul 30, 2006 6:55 pm

Joined: Sun Jun 04, 2006 10:05 am
Location: Eastern Michigan University (Minnesota at heart)
Tim Browne wrote:
xcool wrote:
I can get all but 1 of the centers solved correctly.

How can I re arrange the last center?

OK, since it's only 1 centre, I'm guessing that it's the innermost centre and that it's rotated by 180 degrees, correct? I think any other pattern would mean that either the cube was stickered wrong, or it was taken apart and reassembled wrong. So... asuming that it IS the centremost piece and that it is indeed a 180 degree rotation, hold it so that it's on the bottom and then treat the puzzle as though it's a 3x3 so that R and r both count as the R slice, and D and d count as down... then do (R- D- R+ D- R- D2 R+ D2)^3 and you're done! Hooray! L8r.

No no. I didn't even assemble the inner '3x3' of the face correctly. Like, I need to re arrange just that center. It never was arranged.

_________________
Fridrich
3x3 PB 22.63
3x3 Av 30.57

20, Male
Started cubing Oct 15 '05

Top

 Post subject: Re: Super 5x5x5Posted: Sun Jul 30, 2006 7:36 pm

Joined: Sun Dec 19, 1999 3:02 am
xcool wrote:
No no. I didn't even assemble the inner '3x3' of the face correctly. Like, I need to re arrange just that center. It never was arranged.

Oh, I see. So it's a completely scambled 3x3 block, then. Well, that's going to be a bit more challenging. If you take a look at my page, it'll have solutions for the centre pieces on everything up to 5x5, easily adaptable for even the maximum sized Olympicube if they ever get released. One thing I didn't go into detail in on my page is how ALL of the centre pieces get affected by the patterns for the last layer (I think I know what page I'll be doing next...). If you take the pattern l+ D+ r- D- l- D+ r+ D- (reduced to the pattern notation 2 R 4 on my site... r = column 2, l = column 4, and the D slice starts it's moving towards the right), it moves the top left centre on the front of the cube to the front left on the bottom, to the top right on the front, to the top left on the front. So, if you do 2 R 4 F- 2 R 4 F+ it'll cycle top left, top right and bottom right centres on the front counter-clockwise. If you do r- D- l+ D+ r+ D- l- D+ (4 L 2) it'll drop the front side top right to the bottom side front right, to the front side top left, to the front side top left. So, if you do 4 L 2 F+ 4 L 2 F- it'll cycle the top left, bottom left and top right pieces on the front clockwise. 2 L 4 and 4 R 2 deal with the bottom corner centre pieces on the front in a similar manner, while 3 L 2, 3 R 4, 3 R 2 and 3 L 4 can be used to deal with the edge centre pieces. Exactly how will be left as an exercise for the reader. If this looks WAY too convoluted and messed up, check out my site and it'll have a better explanation, as well as graphics regarding this alternate notation. L8r.

Top

 Post subject: Posted: Mon Aug 07, 2006 3:00 pm

Joined: Fri May 06, 2005 10:13 am
Location: Norway
Hi

(Assuming the unsolved face is the U-centers ...)

Basically u solve all those centers of the "3x3x3" face by using 3-cycles. There is only 2 groups, or orbits if u like, on that 3x3x3 block. The 4 centers next to the middle edges (+-centers) and those 4 ones close to the corners (x-centers). Well, that leaves the middle center (which is attached to the core) which is solved exactly as on the 3x3x3 supercube:

((Rr)' (Ll)' (Uu)2 (Rr) (Ll) (Uu))*2

U can also start by rotating the ENTIRE 3x3x3 block like this if so desired:

(R' L' U2 R L U)*2

The configuration of the +/x centers may be such that u have to do 2 swaps to solve them. In that case first do any 3-cycle involving these centers. Then u are left with a single 3-cycle after that. Yes, just do ANY 3-cycle involving 3 of those centers first

It is IMPOSSIBLE that u are left with a single swap of +-centers and a single swap on the x-centers. In that case not all the centers of the other faces are solved correctly

Good luck

- Per

_________________
"Life is what happens to you while you are busy making other plans" -John Lennon, Beautiful Boy

Top

 Post subject: Posted: Mon Aug 07, 2006 6:29 pm

Joined: Sun Jun 04, 2006 10:05 am
Location: Eastern Michigan University (Minnesota at heart)
perfredlund wrote:
Hi

(Assuming the unsolved face is the U-centers ...)

Basically u solve all those centers of the "3x3x3" face by using 3-cycles. There is only 2 groups, or orbits if u like, on that 3x3x3 block. The 4 centers next to the middle edges (+-centers) and those 4 ones close to the corners (x-centers). Well, that leaves the middle center (which is attached to the core) which is solved exactly as on the 3x3x3 supercube:

((Rr)' (Ll)' (Uu)2 (Rr) (Ll) (Uu))*2

U can also start by rotating the ENTIRE 3x3x3 block like this if so desired:

(R' L' U2 R L U)*2

The configuration of the +/x centers may be such that u have to do 2 swaps to solve them. In that case first do any 3-cycle involving these centers. Then u are left with a single 3-cycle after that. Yes, just do ANY 3-cycle involving 3 of those centers first

It is IMPOSSIBLE that u are left with a single swap of +-centers and a single swap on the x-centers. In that case not all the centers of the other faces are solved correctly

Good luck

- Per
Thanks.

_________________
Fridrich
3x3 PB 22.63
3x3 Av 30.57

20, Male
Started cubing Oct 15 '05

Top

 Post subject: Posted: Thu Aug 10, 2006 6:05 pm

Joined: Sun Jul 09, 2006 2:59 am
Location: Glastonbury, CT (USA)
If you need to flip the center 180 degrees, hold that face on the U side, and perform the "T" PLL algorithm twice.

_________________
Master Pentultimate Auction

Top

 Display posts from previous: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by AuthorPost timeSubject AscendingDescending
 Page 1 of 1 [ 7 posts ]

 All times are UTC - 5 hours