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 Post subject: 4x4x4 parity case?
PostPosted: Tue Dec 03, 2013 2:39 pm 
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Joined: Sun Aug 04, 2013 4:50 am
Location: The Netherlands
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Is this a regular parity case?
How do I solve this state?

Thanks!

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 Post subject: Re: 4x4x4 parity case?
PostPosted: Tue Dec 03, 2013 2:47 pm 
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Joined: Thu Mar 07, 2013 2:38 pm
Location: U.K
No, this is not a regular parity case
Do you solve using Fridrich F2L? If so then this is a standard OLL algorithm both unoriented corners at the front (R2, D, R', U2, R, D', R', U2) and then a single edge OLL parity, and then the application of a PLL parity for both corners.

If you solve using a different method, I'd be happy to see what else I can do.

You're welcome if I helped, I'm sorry if I didn't.

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3x3 PB: 14.87
3x3 average: 20.14


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 Post subject: Re: 4x4x4 parity case?
PostPosted: Tue Dec 03, 2013 2:52 pm 
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Joined: Sat Jan 15, 2011 10:22 am
1NSAN3 wrote:
Is this a regular parity case?
How do I solve this state?

Thanks!


Yes and using an OLL parity alg. (as explained in every 4x4 tutorial, btw)
Rw2 B2 Rw' U2 Rw' U2 x' U2 Rw' U2 Rw U2 Rw' U2 Rw2 U2


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 Post subject: Re: 4x4x4 parity case?
PostPosted: Tue Dec 03, 2013 2:59 pm 
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Joined: Thu Mar 07, 2013 2:38 pm
Location: U.K
EMI94100 wrote:
1NSAN3 wrote:
Is this a regular parity case?
How do I solve this state?

Thanks!


Yes and using an OLL parity alg. (as explained in every 4x4 tutorial, btw)
Rw2 B2 Rw' U2 Rw' U2 x' U2 Rw' U2 Rw U2 Rw' U2 Rw2 U2


Really? I only ever learned the edge OLL parity, using standard CFOP OLL algorithms for the corners, then using PLL algorithms appropriately.

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3x3 PB: 14.87
3x3 average: 20.14


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 Post subject: Re: 4x4x4 parity case?
PostPosted: Tue Dec 03, 2013 3:03 pm 
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Joined: Sun Aug 04, 2013 4:50 am
Location: The Netherlands
mightypuzzle wrote:
No, this is not a regular parity case
Do you solve using Fridrich F2L? If so then this is a standard OLL algorithm both unoriented corners at the front (R2, D, R', U2, R, D', R', U2) and then a single edge OLL parity, and then the application of a PLL parity for both corners.

If you solve using a different method, I'd be happy to see what else I can do.

You're welcome if I helped, I'm sorry if I didn't.


No, I use beginners method :oops: lol
I did solve it however, I just thought there might be a special (simple) algorithm for this particular case.

Reason why I didn't know how to solve this parity is that the only parity alg. that is in the booklet that came with the cube is r2 B2 U2 l2 U2 r' U2 r U2 F2 r F2 l' B2 r2 and there are picture above it that show 2 adjacent dedges swapped, 2 opposite corners swapped, 2 adjacent corners swapped, and 1 flipped dedge.

There IS one other alg. in the booklet that flips 2 opposite dedges: r2 U2 r2 Uw2 r2 u2
I use that for the adjacent dedge swap too with 2 setup moves.

Thanks for helping!

EMI94100 wrote:
1NSAN3 wrote:
Is this a regular parity case?
How do I solve this state?

Thanks!


Yes and using an OLL parity alg. (as explained in every 4x4 tutorial, btw)
Rw2 B2 Rw' U2 Rw' U2 x' U2 Rw' U2 Rw U2 Rw' U2 Rw2 U2


I tried this algorithm on the solved cube, and it gives me the exact same case! Thanks!!!

_________________
- Eric


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 Post subject: Re: 4x4x4 parity case?
PostPosted: Tue Dec 03, 2013 3:13 pm 
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Joined: Thu Mar 07, 2013 2:38 pm
Location: U.K
In that case, solve the single edge flip parity that you've learned and then the 2 edge switch parity algorithm with both corners in the front. That should get you to a stage where you'll be able to solve the cube as a 3x3x3 last layer using the appropriate algorithms.
If you'd rather take the 'easier' option, do a few 2 edge switch algorithms (3x3x3 version, non-parity) R, U, R', U, R, U2, R' until 2 opposite edges need to be switched. Then, solve the corners with whatever algorithm(s) you learned. be it U, R, U', L', U, R', U', L or the opposite. Then orient (twist) the corners to solve them all and do the 2 edge flip parity with the edges that need to be witched at the front and back.

Hope this helps :)

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3x3 PB: 14.87
3x3 average: 20.14


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